(2x-4)^2/5=16

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Solution for (2x-4)^2/5=16 equation: 


x in (-oo:+oo)

((2*x-4)^2)/5 = 16 // - 16

((2*x-4)^2)/5-16 = 0

((2*x-4)^2)/5+(-16*5)/5 = 0

(2*x-4)^2-16*5 = 0

4*x^2-16*x-64 = 0

4*x^2-16*x-64 = 0

4*(x^2-4*x-16) = 0

x^2-4*x-16 = 0

DELTA = (-4)^2-(-16*1*4)

DELTA = 80

DELTA > 0

x = (80^(1/2)+4)/(1*2) or x = (4-80^(1/2))/(1*2)

x = (4*5^(1/2)+4)/2 or x = (4-4*5^(1/2))/2

4*(x-((4-4*5^(1/2))/2))*(x-((4*5^(1/2)+4)/2)) = 0

(4*(x-((4-4*5^(1/2))/2))*(x-((4*5^(1/2)+4)/2)))/5 = 0

(4*(x-((4-4*5^(1/2))/2))*(x-((4*5^(1/2)+4)/2)))/5 = 0 // * 5

4*(x-((4-4*5^(1/2))/2))*(x-((4*5^(1/2)+4)/2)) = 0

( x-((4*5^(1/2)+4)/2) )

x-((4*5^(1/2)+4)/2) = 0 // + (4*5^(1/2)+4)/2

x = (4*5^(1/2)+4)/2

( x-((4-4*5^(1/2))/2) )

x-((4-4*5^(1/2))/2) = 0 // + (4-4*5^(1/2))/2

x = (4-4*5^(1/2))/2

x in { (4*5^(1/2)+4)/2, (4-4*5^(1/2))/2 }

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